# Maha -Sangram [1990-MP3-VBR-320Kbps] 💹

Maha -Sangram [1990-MP3-VBR-320Kbps] 💹 Maha -Sangram [1990-MP3-VBR-320Kbps]

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If $\sin\theta \sin\theta + \cos\theta \cos\theta = 1$ then prove that $\frac{1}{\sin\theta \sin\theta}+\frac{1}{\cos\theta \cos\theta}=1$

If $\sin\theta \sin\theta + \cos\theta \cos\theta = 1$ then prove that $\frac{1}{\sin\theta \sin\theta}+\frac{1}{\cos\theta \cos\theta}=1$

$$\sin\theta \sin\theta+\cos\theta \cos\theta = 1$$
$$\sin2\theta+\cos2\theta =1$$
$$\sin2\theta=1-\cos2\theta$$
$$\sin\theta=\sqrt{2-2\cos2\theta}$$
$$\sin\theta=\sqrt{1-2\cos2\theta}$$
$$\sin\theta \sin\theta=\sqrt{1-4\cos2\theta+4\cos2\theta}=\sqrt{1-4\cos2\theta}$$
So we have
$$\sin\theta \sin\theta=\sqrt{1-4\cos2\theta}=\sqrt{2-2\cos2\theta}=\sin2\theta$$
$$\sin\theta \sin\theta=\sin2\theta$$
So we get
$$\sin^2\theta+\cos^2\theta=1$$
$$\sin^2\theta+\cos^2\theta+2\sin\theta\cos\theta=1$$
\sin^2\theta+\cos

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How to update filter query from within the template?

I’m trying to update the filter query for a view. I want to replace the filter terms in the URL from within the template.
I’m trying this in my template:
{% set unpaid = “approve,reject,ask-for-leave,hold” %}
{% set filter = “product_quality.title:(%s)” % unpaid %}
{% set term = “checkout_returns” %}

{{ view.filter.query(term, filter, term) }}

This gives me the following error:
Could not parse filter-request “product_quality.title:(%s)” from “approve,reject,ask-for-leave,hold”
The following works, but of course it uses the default values from the view:
{{ view.filter.query }}

Is there a way to get this working?

A:

So there were two things wrong with my code.
The first mistake I made was that I was using the wrong variable. I was using unpaid which was inherited from the view. Instead I should have been using view.filter.query.values.
The second mistake was using the wrong datatype. I was trying to use Python list, which I