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Why does Haskell’s () give unpredictable results when given even a seemingly equal list?
Just as the title says, for example:
take 10 $ [[True,False],[True,False]..]
This code should simply return False, since the first list is empty. But the output is False for the first and True for the second, or 1 for the first and 0 for the second, or 4 for the first and 3 for the second, etc.
Why is this, and what is the solution?
The reason this happens is that there are a lot of different ways that a tuple of a form [True, False] can be reordered. For example, the two elements could be swapped or the first element could be omitted, leaving you with [False, True]. So, it ends up being hard to say with certainty what order the two values are in. For example, given a list of the form [[True, False], [True, False]], it’s not always possible to decide if that last True will appear before or after the first False.
To prevent the order from being reversed, the function is defined using the strict version of the tuple operation () instead of the functor () or the safe version (), where you bind your variables with a transformer and use the safe version. If you use the safe version, you can rely on the fact that the ordering of a tuple won’t be reversed if it’s reordered. The safe version is semantically equivalent to the unsafe version, but it’s an optimization of the safe version.
The () function is strict by
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